What happens when you attempt to compile and run the following code?#include <vector>#include <iostream>#include <algorithm>using namespace std;template<class T>struct Out {ostream & out;Out(ostream & o): out(o){}void operator()(const T & val ) {out<<val<<" ";}};struct Sequence {int start;Sequence(int start):start(start){}int operator()() {return start++ ; }};int main() {vector<int> v1(10);generate(v1.rbegin(), v1.rend(), Sequence(1));rotate(v1.begin(),v1.begin() + 1, v1.end() );for_each(v1.begin(), v1.end(), Out<int>(cout) );cout<<endl; return 0;}Program outputs:
What happens when you attempt to compile and run the following code?#include <iostream>#include <fstream>#include <string>#include <list>#include <algorithm>#include <iomanip>using namespace std;class B { int val;public:B(int v=0):val(v){}int getV() const {return val;}operator int() const { return val; };};template<class T>struct Out {ostream & out;Out(ostream & o): out(o){}void operator() (const T & val ) {out<<setw(3)<<hex<<val; } };int main () {int t[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};fstream f("test.out", ios::trunc|ios::out);list<B> l(t, t+10);for_each(l.begin(), l.end(), Out<B>(f));f.close();f.open("test.out");for( ; f.good() ; ) {B i;f>>i;cout<<i<<" ";}f.close();return 0;}
What will happen when you attempt to compile and run the code below, assuming that you enter the following sequence: one two three<enter>?#include <iostream>#include <string>using namespace std;int main (){string a;cin>>a;cout<<a<<endl;return 0;}Program will output:
What will happen when you attempt to compile and run the following code?#include <iostream>#include <map>#include <vector>#include <sstream>#include <string>using namespace std;int main() {int t[] = { 3, 4, 2, 1, 0, 3, 4, 1, 2, 0 };vector<int> v(t, t + 10);multimap<int, string> m;for (vector<int>::iterator i = v.begin(); i != v.end(); i++) { stringstream s;s << *i << *i; m.insert(pair<int, string>(*i, s.str()));}pair<multimap<int, string>::iterator, multimap<int, string>::iterator> range; range = m.equal_range(2); for (multimap<int, string>::iterator i = range.first; i != range.second; i++) { cout << i?>first << " ";}return 0;}The output will be:
What happens when you attempt to compile and run the following code?#include <vector>#include <iostream>#include <algorithm>using namespace std;class B { int val;public:B(int v):val(v){}int getV() const {return val;} bool operator < (const B & v) const { return val>v.val;} }; ostream & operator <<(ostream & out, const B & v) { out<<v.getV(); return out;} template<class T>struct Out { ostream & out;Out(ostream & o): out(o){}void operator() (const T & val ) { out<<val<<" "; } };int main() {B t1[]={3,2,4,1,5};B t2[]={5,6,8,2,1};vector<B> v1(10,0);sort(t1, t1+5);sort(t2, t2+5);set_intersection(t1,t1+5,t2,t2+5,v1.begin());for_each(v1.begin(), v1.end(), Out<B>(cout));cout<<endl; return 0;}Program outputs:
What happens when you attempt to compile and run the following code?#include <iostream>#include <set>#include <vector>using namespace std;int main(){int t[] ={ 3, 4, 2, 1, 6, 5, 7, 9, 8, 0 };vector<int>v(t, t+10);multiset<int> s1(v.begin(),v.end());s1.insert(v.begin(),v.end());pair<multiset<int>::iterator,multiset<int>::iterator> range; range = s1.equal_range(6); while (range.first != range.second) { cout<<*range.first<<" "; range.first++;}return 0;}
